sin37°30' sin7°30' =

sin37°30' sin7°30' =

Ответ:

sin37°30' sin7°30' =(1/2*[cos30°-cos45°]=(1/2)*[sqrt(3)/2-sqrt(2)/2]=

=(1/4)*[sqrt(3)-sqrt(2)]

Ответ #2:

sin37°30' sin7°30' =(1/2*[cos30°-cos45°]=(1/2)*[sqrt(3)/2-sqrt(2)/2]=

=(1/4)*[sqrt(3)-sqrt(2)]

Источник: https://znanija.com/task/140629