sin(arccos4/7)=

sin(arccos4/7)=

Ответ:

sin(arccos(4/7))

sin(arcsin(4/7))=4/7

cos^2A=1-sin^2A

cos^2(4/7)=1-(4/7)^2=33/49

cos(4/7)=sqrt(33)/7

sin(arccos(4/7))= sqrt(33)/7

Источник: https://znanija.com/task/122451