(1+y)(2-y) ²-(2+y)(1-y) ²-3(1-y ²) при : y=-1, 4; y=2, 5.

(1+y)(2-y) ²-(2+y)(1-y) ²-3(1-y ²) при : y=-1, 4; y=2, 5.

Ответ:

(1+y)(2-y) ²-(2+y)(1-y) ²-3(1-y ²) при : y=-1,4 (1-1.4)(2+1.4)² - (2-1.4)(1+1.4)² - 3(1+1.4²)= -0.4*3.4² - 0.6*2.4² - 3*2.96= -0.4*11.56 - 0.6*5.76 - 3*2.96= -4.624 - 3.456 - 8.88 = -16.96 при : y=2,5 (1+2.5)(2-2.5)² - (2+2.5)(1-2.5)² - 3(1-2.5²)= 3.5*(-0.5)² - 4.5*(-1.5)² - 3*(-5.25)= 3.5*0.25 - 4.5*2.25 - (-15.75)= 0.875 - 10.125 +1 5.75 = 6.5

Источник: https://znanija.com/task/179993